For a carbon atom that is sp2 hybridized, I understand that the electron configuration would be Yes, 1s2 2s1 2p3 which is a 2s up arrow,and 3 orbtials that are 2p up arrows but then since the four bonds hybridize to form four sp3 hybrid bonds how do I write this?

Also for an sp carbon is this electron configuration correct? 1s orbital with an up and down arrow, 2sp orbital with up and up, and 2p orbital with up and up? Would I write this as 1s2 2s2 2p2?

Thank you for the help

C is 1s2 2s2 2p1 2p1 and in sp3 hybrids the 1 2s orbital mixes with the 3 2p orbitals to form 4 bonds, all alike, as sp3 hybrids (hybrids as in not an s and not a p but four mixed s & p to form sp3). We write that as 1s2 sp3 sp3 sp3 sp3 with one electron in each of the 4 sp3 spots.

In SP2 hybrids, the 1 2s mixes with just 2 of the 2p orbitals to form
1s2 sp2 sp2 sp2 2p with one electron in each.

In sp hybrids, 1 2s electron mixes with just 1 2p orbital to give
1s2 sp sp 2p 2p

This site probably does a better job since it shows the up and down arrows.
http://en.wikipedia.org/wiki/Orbital_hybridisation

Ok I think I understand now, thank you very much for the explanation and the website as well. It really helped!!

For a carbon atom that is sp2 hybridized, the electron configuration would be written as 1s2 2s1 2p2. This represents the distribution of electrons in the carbon atom before hybridization.

To represent the hybridization formed by the sp2 orbitals, you would write it as sp2. This means that one s orbital and two p orbitals have hybridized to form three sp2 hybrid orbitals.

Regarding an sp carbon atom, your electron configuration is almost correct. It would be written as 1s2 2s1 2p1 since only one of the three p orbitals is involved in hybridization.

To summarize, the electron configurations for the two cases are:

1. sp2 hybridized carbon: 1s2 2s1 2p2, with the hybridization represented as sp2.
2. sp hybridized carbon: 1s2 2s1 2p1, with the hybridization represented as sp.

For a carbon atom that is sp2 hybridized, the correct electron configuration is as follows:

1s2 2s1 2px1 2py1 2pz0

In this case, the carbon atom has one electron in the 2s orbital, one electron in the 2px orbital, and one electron in the 2py orbital. The 2pz orbital remains unoccupied. This configuration represents the three valence electrons for a carbon atom that is ready to form three bonds.

When the carbon atom forms the four sp3 hybridized bonds, it rearranges its electron configuration. To represent this, you can write the hybridized electron configuration as:

1s2 2sp3 2p0

This is because during hybridization, one of the 2s electrons moves to the 2p orbital to allow for hybridization, resulting in four sp3 hybrid orbitals and one unoccupied p orbital.

Regarding your second question, for an sp hybridized carbon atom, the electron configuration would be:

1s2 2sp2 2pz0

In this case, the carbon atom has two electrons in the 2s orbital, two electrons in the 2sp hybrid orbitals, and no electrons in the 2pz orbital. The 2pz orbital remains unoccupied. This configuration represents the two valence electrons for a carbon atom that is ready to form two bonds.

I hope this clears up any confusion. Let me know if you have any further questions!