Given the area of the figure, find its perimeter to the nearest tenth.

1. A = 90 ft^2; number of squares: 6.

2. A baseball diamond is a square with an area of 8100 square feet. The length of the diagonal of any square is equal to √2 times it's side length. Finds fhe distance from home plate to second base (the length of the diagonal) to the nearest hundredth of a foot.

Answers:

1. The perimeter of the figure is 54. 2 ft.?

2. The length from home plate to second base is 127. 28 ft.?

Are my answers correct?

To find the perimeter of a figure, you need to know the lengths of its sides. In the first question, you are given the area of the figure and the number of squares it is made up of. To find the perimeter, we need to determine the side length of each square.

1. The area of the figure is given as 90 ft^2, and it is made up of 6 squares. To find the side length of each square, you divide the total area by the number of squares: 90 ft^2 / 6 = 15 ft^2.

Since a square has all sides equal, each square has a side length of 15 ft. Since there are 6 squares, the total perimeter is the sum of all the side lengths, which is 6 * 15 ft = 90 ft.

So, the perimeter of the figure is 90 ft.

2. In the second question, you are given the area of a square, which represents the baseball diamond, and you need to find the distance from home plate to second base, which is the length of the diagonal of the square.

The area of the square is given as 8100 square feet. To find the side length of the square, you take the square root of the area: √8100 = 90 ft.

The length of the diagonal of any square is equal to √2 times its side length. So, the length from home plate to second base (diagonal) is √2 * 90 ft.

Calculating this value, we get √2 * 90 ft ≈ 127.28 ft.

Rounding to the nearest hundredth, the distance from home plate to second base is approximately 127.28 ft.