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Math 3

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for football tryouts at a local school, 12 coaches and 42 players will split into groups. each group will have the same numbers of coaches and players. what is the greatest number of groups that can be formed? how many coaches and players will be in each of these groups?Please help answer questions. thanks

  • Math 3 -

    Factors of 42:
    1, 42, 2, 21, 3, 14, 6, 7

    Factors of 12:
    1, 12, 2, 6, 3, 4

    What is the largest common factor?

  • Math 3 -

    3 is the largest common factor. Therefore, there will be 3 groups with 4 coaches and 14 players. You have to read the question carefully. When I first read the question, I thought I needed to have equal player to coach ratio in each group. I went crazy b/c I have player left over. When I read it several times, I realized I needed to have the same number of coaches per group and the same number of player per group. So the answer to the second part of the questions is 4 coaches and 14 players in each of the 3 groups.

  • Math 3 -

    The gcf is 6

  • Math 3 -

    idk

  • Math 3 -

    Don't know help me

  • Math 3 -

    Pls😐😐😐

  • Math 3 -

    3 coches and 6 students in each group

  • Math 3 -

    6 Groups, 2 Coaches, and 7 Players

    The GCF of 12 & 42 is 6.

    What I did was divide 12 and 42 by 6.

    12 divided by 6 is 2. So there are 2 coaches
    42 divided by 6 is 7. So there are 7 players

  • Math 3 -

    6 coaches and players in each group

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