Algebra 1

posted by Anonimous

A rectangle's length is 3 cm less than twice it's width. if the length is decreased by 2 cm and the width is decreased by 1 cm, the perimeter will be 24 cm. find the dimensions of the original rectangle.

  1. Steve

    width: w
    length: 2w-3

    after the changes, we have

    (2w-3-2 + w-1) = 24
    Now just solve for w, the original width.

  2. rob

    w=10

  3. max

    The length of a rectangle is 3 cm less than twice its width. If the length is decreased by 2 cm and the width is decreased by 1 cm, the perimeter will be 24 cm. find the dimensions of the original rectangle.
    Find X, 'find equation, and find answer plz.

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