Algebra 1
posted by Anonimous
A rectangle's length is 3 cm less than twice it's width. if the length is decreased by 2 cm and the width is decreased by 1 cm, the perimeter will be 24 cm. find the dimensions of the original rectangle.

Steve
width: w
length: 2w3
after the changes, we have
(2w32 + w1) = 24
Now just solve for w, the original width. 
rob
w=10

max
The length of a rectangle is 3 cm less than twice its width. If the length is decreased by 2 cm and the width is decreased by 1 cm, the perimeter will be 24 cm. find the dimensions of the original rectangle.
Find X, 'find equation, and find answer plz.
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