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If the root of the equation x²-8x+m=0 exceeds the other by 4 then the value of m is

  • math -

    the roots are

    x = (8±√(64-4m))/2 = 4±√(16-m)

    So, we have

    4+√(16-m) = 4-√(16-m) + 4
    2√(16-m) = 4
    √(16-m) = 2
    16-m = 4
    m = 12

    So, the function is

    x^2-8x+12, and the roots are 2 and 6

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