a solution is prepared by mixing 1.0 grams of benzen(c6h6) in 100g of water to create a solution total volume of 100ml.calculate the molarity,mass percent,mole fraction and molarity of benzene in the solution

C6H6 --> 6*12 + 6 = 78 grams/mol

so we have 1/78 mol

1/78 mol in 0.1 liter --> 10/78 molarity etc

To calculate the molarity, mass percent, mole fraction, and molality of benzene in the solution, we need to calculate the moles of benzene and the total moles of the solution.

First, let's calculate the moles of benzene:
Molar mass of benzene (C6H6) = 12.01 g/mol (C) + 1.01 g/mol (H) x 6 = 78.11 g/mol.

Moles of benzene = Mass of benzene / Molar mass of benzene.
Moles of benzene = 1.0 g / 78.11 g/mol = 0.0128 mol.

Next, let's calculate the total moles of the solution:
Moles of water = Mass of water / Molar mass of water.
Molar mass of water (H2O) = 1.01 g/mol (H) x 2 + 16.00 g/mol (O) = 18.02 g/mol.
Moles of water = 100 g / 18.02 g/mol = 5.55 mol.

Total moles of the solution = Moles of benzene + Moles of water.
Total moles of the solution = 0.0128 mol + 5.55 mol = 5.56 mol.

Now, let's calculate the molarity of benzene:
Molarity = Moles of solute / Volume of solution in liters.
Volume of solution = 100 mL = 100 cm^3 = 100/1000 = 0.1 L.

Molarity of benzene = 0.0128 mol / 0.1 L = 0.128 M.

Next, let's calculate the mass percent of benzene:
Mass percent of benzene = (Mass of benzene / Mass of solution) x 100.
Mass of solution = Mass of benzene + Mass of water = 1.0 g + 100 g = 101 g.

Mass percent of benzene = (1.0 g / 101 g) x 100 = 0.99%.

Now, let's calculate the mole fraction of benzene:
Mole fraction = Moles of a component / Total moles of the solution.

Mole fraction of benzene = 0.0128 mol / 5.56 mol = 0.0023.

Finally, let's calculate the molality of benzene:
Molality = Moles of solute / Mass of solvent in kg.

Mass of water = 100 g = 100/1000 = 0.1 kg.

Molality of benzene = 0.0128 mol / 0.1 kg = 0.128 mol/kg.

So, the molarity of benzene in the solution is 0.128 M, the mass percent of benzene is 0.99%, the mole fraction of benzene is 0.0023, and the molality of benzene is 0.128 mol/kg.