# Math

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x^(log10x)=100

I'm not sure how to do this at all...

• Math -

I will assume you meant ...

x^(log10 x = 100

then by definition:

logx 100 = log10x
changing to a common base of the log ...

log10 100/logx = logx/log1010
2/log10x = log10 x/1
(log10 x)^2 = 2
log10 x =√2

using my calculator
x = appr 25.9546 or x = appr .03853

(both answers can be verified)

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