Math
posted by Tyler .
x^(log10x)=100
I'm not sure how to do this at all...

I will assume you meant ...
x^(log_{10} x = 100
then by definition:
log_{x} 100 = log_{10}x
changing to a common base of the log ...
log_{10} 100/log_{x} = log_{x}/log_{10}10
2/log_{10}x = log_{10} x/1
(log_{10} x)^2 = 2
log_{10} x =√2
using my calculator
x = appr 25.9546 or x = appr .03853
(both answers can be verified)
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