If student A measures a laptop computer to be 37.2 cm long, and student B measures 36.7 cm, what is the percentage error?

I do not know because I do not know the true value.

However I can give the percentage range from the average of the two.
(37.2+36.7)/2 = 36.95

difference = +/- 0.25

100* .25/36.95 = + or - .68%

To calculate the percentage error, you need to find the difference between the measured value and the actual value, and then express it as a percentage of the actual value.

In this case, we are comparing the measurements of student A and student B to find the percentage error. However, we don't have the actual value of the laptop computer's length. So, we can't determine the actual error or the percentage error accurately.

To calculate the percentage error, you need the actual value or a reference value to compare the measurements against. Without that information, it is not possible to determine the percentage error in this scenario.