a gun fires Aa bullet of mass 50g the bullet moving with a velocity of 100m/s strikes a sandbag get embedded after travelling 10cm calculate the resistance force exerted by the sand bag on the bulle
mass=50g=0.05kg
v=500
s=10cm=0.01m
K.E= 1/2mv^2
1/2x0.05x500x500
=6,250m/s^2
force*distance=1/2 m v^2
solve for frictional force
100N
wrong ans
Is it 2500N ?
Using work energy theorem,
Wd = 1/2mv^2 - 1/2mu^2
Here, v is zero.
Mass is 0.05 kg And displacemt is 0.1 m.
Wd = -1/2 * 0.05 * 10000
Force * displacement = Wd
Thus, force can be calculated nd negative sign will indicate that it is resistant force
To calculate the resistance force exerted by the sandbag on the bullet, we can use the principle of conservation of momentum.
The momentum of an object is defined as the product of its mass and velocity:
Momentum = mass * velocity
In this case, the mass of the bullet is given as 50g, which is equivalent to 0.05kg. The velocity of the bullet is given as 100m/s.
Initial momentum of the bullet = mass * initial velocity = 0.05kg * 100m/s = 5 kg·m/s
The bullet comes to rest after embedding in the sandbag. This means the final velocity of the bullet is 0m/s.
Final momentum of the bullet = mass * final velocity = 0.05kg * 0m/s = 0 kg·m/s
According to the principle of conservation of momentum, the initial momentum of the bullet is equal to its final momentum:
Initial momentum = Final momentum
5 kg·m/s = 0 kg·m/s
Now, let's calculate the change in momentum:
Change in momentum = Final momentum - Initial momentum
= 0 kg·m/s - 5 kg·m/s
= -5 kg·m/s
The negative sign indicates that the momentum of the bullet changed direction, which is expected since it came to rest.
The change in momentum is equal to the impulse applied to the bullet by the sandbag. Impulse is defined as the product of force and time:
Impulse = force * time
In this case, the time of impact is not explicitly given. However, we can assume it to be negligible and approximate the impulse as the change in momentum:
Impulse = Change in momentum = -5 kg·m/s
The impulse is equal to the average force applied multiplied by the time taken to stop the bullet. Since time is negligible, the impulse is approximately equal to the resistance force exerted by the sandbag.
Therefore, the resistance force exerted by the sandbag on the bullet is approximately -5 Newtons. The negative sign indicates that the force is acting in the opposite direction of the initial velocity of the bullet.