boy weighting 30 kg is riding a bicycle weighting 50 kilograms if the bycycle is moving at a speed of 90 kilometres per hour towards the west find the linear momentum of the bycycle boy system in s i units

200 kgm/s

To find the linear momentum of the bicycle-boy system, we need to calculate the total mass of the system (m) and multiply it by the velocity of the system (v).

Given:
Mass of the boy (m1) = 30 kg
Mass of the bicycle (m2) = 50 kg
Velocity of the system (v) = 90 km/h towards the west

First, let's convert the velocity from km/h to m/s:
1 km/h = 1000 m/3600 s
Therefore, the velocity is 90 km/h * 1000 m/3600 s = 25 m/s towards the west.

Now, we can calculate the total mass of the system:
m = m1 + m2
= 30 kg + 50 kg
= 80 kg

Next, we can calculate the linear momentum of the system:
Linear momentum (p) = m * v
= 80 kg * 25 m/s
= 2000 kg*m/s

Therefore, the linear momentum of the bicycle-boy system in SI units is 2000 kg*m/s.

To find the linear momentum of the bicycle-boy system, we need to calculate the total mass of the system and multiply it by the velocity.

First, we need to find the total mass of the system. We add the masses of the boy and the bicycle together:

Mass of the boy = 30 kg
Mass of the bicycle = 50 kg

Total mass of the system = Mass of the boy + Mass of the bicycle
= 30 kg + 50 kg
= 80 kg

Now, we need to convert the speed from km/h (kilometers per hour) to m/s (meters per second) because SI units use the metric system.

1 km = 1000 m
1 hour = 3600 seconds

Speed in m/s = Speed in km/h * (1000 m/1 km) * (1 hour/3600 seconds)

Speed in m/s = 90 km/h * (1000/1) * (1/3600)
= 90 * (1000/3600) m/s
= 25 m/s (rounded to two decimal places)

Lastly, we calculate the linear momentum of the bicycle-boy system as:

Linear momentum = Total mass of the system * Velocity
= 80 kg * 25 m/s
= 2000 kg·m/s

Therefore, the linear momentum of the bicycle-boy system in SI units is 2000 kg·m/s.

Momentum=total mass*velocity change km/hr to m/s

90km/hr*(1hr/3600s)*1000m/1km= 90/3.6 m/s

check my thinking