geometry

posted by Anonymous

solution of the questions The sides of a quadrilateral ABCD are 6 cm, 8 cm, 12 cm and 14 cm (taken in order) respectively, and the angle between the first two sides is a right angle. Find its area.

  1. bobpursley

    use Heron's formula.

    draw a line from the end of the 6 and 8 cm side, forming a right triangle. The length of that is 10 cm (Pythagorean)

    Now you have two triangles. Figure the area of each using Heron's formula,then add them.
    semiperimert s=1/2 (a+b+c) on each triangle

    Area=sqrt[(s-a)(s-b)(s-c)s] HERO's formula

    do that for both triangles, then add.

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