A JAR CONTAINING 3 RED 4 BLUE AND 5 WHITE MARBLES WHATS THE CHANCE OF DRAWING FIRST A RED AND THEN WITHOUT REPLACEMENT A WHITE MARBLE?
12 marbles
first draw 3/12 = 1/4
second draw 5/11
1/4 * 5/11 = 5/44
To find the probability of drawing first a red marble and then without replacement, drawing a white marble, we need to calculate it step by step.
Step 1: Calculate the probability of drawing a red marble first:
The total number of marbles in the jar is 3 red + 4 blue + 5 white = 12 marbles.
Therefore, the probability of drawing a red marble first is 3 red marbles / 12 total marbles = 1/4.
Step 2: Calculate the probability of drawing a white marble without replacement:
After drawing a red marble, we are left with 11 marbles in total (since we did not replace the marble we drew). Out of these, there are 5 white marbles remaining.
Therefore, the probability of drawing a white marble without replacement is 5 white marbles / 11 total marbles = 5/11.
Step 3: Calculate the overall probability:
Since we need both events to happen consecutively, the probabilities of the individual events need to be multiplied together.
So, the probability of drawing first a red marble and then without replacement, drawing a white marble is (1/4) * (5/11) = 5/44.
Therefore, the probability of drawing first a red marble and then without replacement, drawing a white marble is 5/44.