Calculate the volume(at STP) Of these compounds (a) 1,5 mol oxygen gas (b) 0,01 mol of hydrogen chloride gas (c) 3 mol helium
A)1 mol O2= 22,4 dm 1,5 mol O2 will occupy a volume of 33,6
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To calculate the volume of a gas at STP (Standard Temperature and Pressure), we use the ideal gas law equation:
PV = nRT
Where:
P = pressure (in atmospheres, atm)
V = volume (in liters, L)
n = number of moles of gas
R = ideal gas constant (0.0821 L·atm/(mol·K))
T = temperature (in Kelvin, K)
For STP specifically, the temperature is 273.15 K, and the pressure is 1 atm.
Let's calculate the volume for each compound:
(a) 1.5 mol oxygen gas:
n = 1.5 mol
P = 1 atm
T = 273.15 K
R = 0.0821 L·atm/(mol·K)
Plug the values into the ideal gas law equation:
PV = nRT
V = (nRT) / P
V = (1.5 mol * 0.0821 L·atm/(mol·K) * 273.15 K) / 1 atm
Calculating this would give you the volume of oxygen gas at STP.
(b) 0.01 mol hydrogen chloride gas:
n = 0.01 mol
P = 1 atm
T = 273.15 K
R = 0.0821 L·atm/(mol·K)
Plug the values into the ideal gas law equation:
PV = nRT
V = (nRT) / P
V = (0.01 mol * 0.0821 L·atm/(mol·K) * 273.15 K) / 1 atm
Calculating this would give you the volume of hydrogen chloride gas at STP.
(c) 3 mol helium:
n = 3 mol
P = 1 atm
T = 273.15 K
R = 0.0821 L·atm/(mol·K)
Plug the values into the ideal gas law equation:
PV = nRT
V = (nRT) / P
V = (3 mol * 0.0821 L·atm/(mol·K) * 273.15 K) / 1 atm
Calculating this would give you the volume of helium at STP.
You know that one(1) mole of any gas at STP occupies 22.4L.
So # mol x 22.4 L/mol = ? L