what is the molar concentration of a solution containing 15,0 g of pottasium chloride in 1,30 dm3 of solution
mols KCl = grams/molar mass
M = mols KCl/1.30 dm^3
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To find the molar concentration of a solution, also known as molarity (M), we can use the formula:
Molarity (M) = (number of moles of solute) / (volume of solution in liters)
First, we need to calculate the number of moles of potassium chloride using its molar mass. The molar mass of potassium chloride (KCl) is:
Mass of K = 39.10 g/mol
Mass of Cl = 35.45 g/mol
Molar mass of KCl = Mass of K + Mass of Cl = 39.10 + 35.45 = 74.55 g/mol
We are given that the mass of potassium chloride in the solution is 15.0 g and the volume is 1.30 dm³.
Next, we need to convert the volume from dm³ to liters. Since 1 dm³ is equal to 1 liter, the volume remains the same.
The molar concentration (Molarity) can now be calculated:
Molarity (M) = (number of moles of solute) / (volume of solution in liters)
To find the number of moles of potassium chloride, we can use the formula:
Number of moles = Mass / Molar mass
Number of moles of KCl = 15.0 g / 74.55 g/mol
Now, we substitute the values into the molarity formula:
Molarity (M) = (number of moles of KCl) / (volume of solution in liters)
= (15.0 g / 74.55 g/mol) / (1.30 dm³)
Now, we calculate the molarity:
Molarity (M) = (15.0 g / 74.55 g/mol) / (1.30 L)
= 0.1787 mol / 1.30 L
≈ 0.1379 M
Therefore, the molar concentration of the solution containing 15.0 g of potassium chloride in 1.30 dm³ of solution is approximately 0.1379 M.