If the density of atoms in a material is 1026 metres-3, and 0.04% of a beam of neutrons is stopped in a 2 cm slab of the material
What is the cross section ??
No idea can anyone supply a formula ??
thanks
If the density of atoms in a material is 10[{MathJax fullWidth='false' ^{26} m^{-3} }], and 0.04% of a beam of neutrons is stopped in a 2 cm slab of the material, what is the cross section?
To calculate the cross section, you can use the formula:
Cross section = (Number of stopped particles) / (Number of incident particles) / (Density of atoms)
In this case, you are given the density of atoms as 1026 meters^-3, and 0.04% of a beam of neutrons is stopped in a 2 cm slab of the material. To calculate the cross section, you need to know the number of stopped particles and the number of incident particles.
The number of stopped particles can be determined by multiplying the number of incident particles (beam of neutrons) by the percentage of particles stopped. In this case, if you have, for example, 100 neutrons in the incident beam and 0.04% of them are stopped, the number of stopped particles would be 100 * 0.04/100 = 0.04 particles.
The number of incident particles is not directly given in the question, so you would need additional information or assumptions to calculate it. Once you have the number of stopped particles and the number of incident particles, you can then divide by the density of atoms to find the cross section.
Please note that the given question does not provide enough information to calculate the cross section precisely. The number of incident particles is missing, which is crucial for the calculation.