math
posted by Adam .
If a bicycle wheel has traveled f/π feet after n complete revolutions, what is the length in feet of the diameter of the bicycle wheel?
A. f/nπ^2
B. π^2/fn
C. nf/π^2
D. nf/π^2
E. f/n

n rotations = f/π ft
1 rotation = fπ/n ft
2πr = fπ/n
r = f/(2n) ft
diameter = 2r = f/n ft 
thanks reiny

(F/pi) feet......in N rotation
?.............in 1 rotation
(F/ pi × N)feet
C= 2pi r
(F/ pi × N) = 2pi r
r = ( F/ 2(pi^2)N)
Answer....Dia = F/(pi N^2)