a mass of 80 grams of hydrogen gas is heated with nitrogen gas to produce ammonia gas .what is the mass of ammonia that will be produced

H2 is 2 grams/mol

so we have 40 mols of H2 which is 80 mols of H

for each mol of H we get 1/3 mol of NH3
so we get 80/3 mols of NH3

NH3 is 14+3 = 17 grams/mol

(80/3)mols * 17 grams/mol = 453 grams NH3

To determine the mass of ammonia that will be produced, we first need to understand the chemical equation for the reaction between hydrogen and nitrogen to form ammonia.

The balanced equation for this reaction is:

3H2 + N2 -> 2NH3

From the equation, we can see that three molecules of hydrogen gas (H2) react with one molecule of nitrogen gas (N2) to produce two molecules of ammonia gas (NH3).

Now, let's solve the problem step by step:

1. Calculate the number of moles of hydrogen gas. To do this, we divide the mass of the hydrogen gas by its molar mass. The molar mass of hydrogen (H2) is approximately 2 grams/mol.

Number of moles of H2 = mass of H2 / molar mass of H2
Number of moles of H2 = 80 grams / 2 grams/mol
Number of moles of H2 = 40 moles

2. Since the balanced equation shows that three molecules of hydrogen gas react with one molecule of nitrogen gas, the number of moles of nitrogen gas required can be calculated by dividing the number of moles of hydrogen gas by 3.

Number of moles of N2 = number of moles of H2 / 3
Number of moles of N2 = 40 moles / 3
Number of moles of N2 = 13.33 moles

3. Finally, using the balanced equation, we can determine the number of moles of ammonia gas produced. According to the equation, two molecules of ammonia are formed for every one molecule of nitrogen gas.

Number of moles of NH3 = (2/1) * number of moles of N2
Number of moles of NH3 = (2/1) * 13.33 moles
Number of moles of NH3 = 26.67 moles

4. To find the mass of ammonia produced, we multiply the number of moles of NH3 by its molar mass. The molar mass of ammonia (NH3) is approximately 17 grams/mol.

Mass of NH3 = number of moles of NH3 * molar mass of NH3
Mass of NH3 = 26.67 moles * 17 grams/mol
Mass of NH3 = 453.39 grams

Therefore, approximately 453.39 grams of ammonia gas will be produced from the reaction of 80 grams of hydrogen gas with nitrogen gas.