f 8.77 g of KI are

dissolved in enough water
to make 4.75 L of solution, what is the molarity
of the solution?

mols KI = grams/molar mass = ?

Then M = mols/L solution

To determine the molarity of a solution, you need to know the amount of solute (in moles) and the volume of the solution (in liters).

Given:
- Amount of potassium iodide (KI) = 8.77 g
- Volume of solution = 4.75 L

To find the molarity of the solution, we need to first convert the mass of KI into moles using its molar mass. The molar mass of KI is the sum of the atomic masses of potassium (K) and iodine (I).

1. Calculate the molar mass of KI:
- Atomic mass of K (potassium) = 39.10 g/mol
- Atomic mass of I (iodine) = 126.90 g/mol

Molar mass of KI = (39.10 g/mol) + (126.90 g/mol) = 166.00 g/mol

2. Convert grams of KI to moles:
Moles of KI = (8.77 g) / (166.00 g/mol)

3. Calculate the molarity:
Molarity (M) = Moles of solute / Volume of solution
Molarity = Moles of KI / Volume of solution

Substituting the values:
Molarity = (8.77 g / 166.00 g/mol) / 4.75 L

Now calculate the molarity using the given values:

Molarity = (8.77 / 166.00) / 4.75

Molarity = 0.0326 M (rounded to four decimal places)

Therefore, the molarity of the solution is approximately 0.0326 M.