A ball hits a wall horizontally at 6.0 m/s. It rebounds horizontally at 4.4 m/s. The ball is in contact with the wall for 0.040 s. What is the acceleration of the ball?
a = (V-Vo)/t = (-4.4-6)/0.04=-260 m/s^2.
-260
What is v0
How v=-0.04 because according to the question v =0.04
To find the acceleration of the ball, we can use the formula:
acceleration (a) = (final velocity - initial velocity) / time
In this case, the initial velocity (u) of the ball is 6.0 m/s, the final velocity (v) is -4.4 m/s (since it rebounds in the opposite direction), and the time (t) is 0.040 s.
So the formula becomes:
a = (-4.4 m/s - 6.0 m/s) / 0.040 s
Simplifying the equation:
a = (-10.4 m/s) / 0.040 s
a = -260 m/s²
Therefore, the acceleration of the ball is -260 m/s². Note that the negative sign indicates the direction of the acceleration, which is opposite to the initial velocity of the ball.