The approximate distance,S, in feet that an object falls in t seconds when dropped from a height can be found by using the formula S = 16t^2.In 8 seconds, the object will fall
a. 256 feet
b. 1,024 feet
c. 1,084 feet
d. 2,048 feet
e. 15,384 feet
please answer and explain
mmmmhhh ?
Did you try plugging in 8 for t in your given formula ?
- remember you would have to square first
I don't understand what is the question mean
16 * 8 * 8
To find the distance that an object falls in 8 seconds using the formula S = 16t^2, we can substitute t = 8 into the equation:
S = 16(8)^2
S = 16 * 64
S = 1024 feet
Therefore, the object will fall 1024 feet in 8 seconds.
The correct answer is option b. 1,024 feet.
To explain further, this formula is derived from the motion equation for the free fall of an object near the surface of the Earth. When an object is dropped, it accelerates downwards due to gravity. The acceleration, represented as "g", is approximately equal to 32 feet per second squared. Thus, to find the distance an object falls in a given time "t", we can use the formula S = (1/2)g*t^2.
Multiplying the 1/2 by g, which is 32, we get 16. Therefore, the formula is S = 16t^2, where S represents the distance in feet and "t" represents the time in seconds. By plugging in the value of 8 for "t", we found that the object falls 1024 feet.