please find it's factors
2x^3+5x^2+4x+1
thanks
try x = -1 for a zero
2(-1) + 5(1) + 4 (-1) + 1
-2 + 5 - 4 + 1
0
so
(x+1) is a factor, now divide
(x+1)(2x^2 + 3x + 1)
(x+1)(2x+1)(x+1)
can you give me two more factors please.... i've already tried numbers 9 to 25.
I gave you the whole thing factored
(x+1)(2x+1)(x+1)
zeros are
-1 , -1/2, -1
how many factors does this polynomial has? please.. i really need your answers. asap!
Hey, look, you are not paying attention.
it has highest power of 3 so three factors and three zeros
however one of those zeros is repeated, x = -1
so
zeros are -1, -1 , -1/2
and the three factors are
(x+1)
(x+1)
(2x+1)
now check by multiplying those three factors and see if you get
2x^3+5x^2+4x+1
To find the factors of the given polynomial, we need to first check if it can be factored using any of the common techniques, such as factoring by grouping, factoring by using certain patterns (e.g., difference of squares), or applying the rational root theorem. In this case, let's try factoring by grouping.
Step 1: Group the terms in pairs:
(2x^3 + 5x^2) + (4x + 1)
Step 2: Extract the common factors from each group:
x^2(2x + 5) + 1(4x + 1)
Step 3: Now, look for a common binomial factor in the expression. In this case, we can see that there is no common binomial factor.
Therefore, the polynomial 2x^3 + 5x^2 + 4x + 1 cannot be factored further into linear factors.