(-2x^4)^2
y
Again I will assume you mean:
(-2x^4)^2 / y
-2 *-2 = + 4
x^4 * x^4 = x^8
so
4 x^8 / y
which is the same as
4 x^8 y^-1
Here is a link to instructions:
http://www.mathsisfun.com/algebra/variables-exponents-multiply.html
Then to raise one power to another see:
http://mathsfirst.massey.ac.nz/Algebra/Exponents/IntegerExp/RaisePower.htm
I am doing polynomials, is that the same
yes :)
although a polynomial normally has more than one term
for example
x^2 + 2 x + y + y^3 .........
Thank you :)
You are welcome
poly means more than one or many in general
To simplify the expression (-2x^4)^2, we first need to apply the exponent to both the base (-2x^4) and the exponent 2.
Applying the exponent 2 to the base (-2x^4), we multiply the exponent of each factor within the base by 2:
(-2x^4)^2 = (-2)^2 * (x^4)^2
Now we simplify each part separately.
(-2)^2 = 4 (square of -2)
(x^4)^2 = x^(4*2) = x^8 (when we have an exponent raised to another exponent, we multiply the exponents)
Putting it all together, we have:
(-2x^4)^2 = (-2)^2 * (x^4)^2 = 4 * x^8
So the simplified expression is 4x^8.
Regarding the "y" part of your question, I'm not sure what you're asking. Could you please provide more context or clarify your question?