Post a New Question


posted by .

A 45.0 g golf ball is released 2.50 m above the ground. The velocity of the golf ball when it hits the ground is

  • physics -

    45 g has nothing to do with this because m cancels

    (1/2) m v^2 = m g h
    v^2 = 2 g h
    v = sqrt (2 g h) [ worth remembering ]

Answer This Question

First Name
School Subject
Your Answer

Related Questions

More Related Questions

Post a New Question