physics
posted by oo .
A 45.0 g golf ball is released 2.50 m above the ground. The velocity of the golf ball when it hits the ground is

physics 
Damon
45 g has nothing to do with this because m cancels
(1/2) m v^2 = m g h
v^2 = 2 g h
v = sqrt (2 g h) [ worth remembering ]
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