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A car which is traveling at a velocity of 9.6 m/s undergoes an acceleration of 4.2 m/s2 over a distance of 450 m. How fast is it going after that acceleration?

  • physics -

    d = Vi t + (1/2) a t^2
    450 = 9.6 t + 2.1 t^2
    solve quadratic for t
    then
    v = Vi + a t
    v = 9.6 + 4.2 t

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