a baseball is thrown from a mound .833ft above ground level ,to home plat 60.5 feet away. the ball is released horizontally from the pitcher with a velocity of 139ft/s when the pitchers hand is 5.3ft above the mound. a)how long will it take to reach home plate? b) how far did the ball drop on the way to home plate and c) what would be the height of the ball above the ground when it reaches home plate?

a. time=distance/velocity=60.5/139 seconds

b. drop= 4.9t^2

c. what is 5.3+.833- drop?

To answer these questions, we can use basic physics equations and principles, specifically related to projectile motion. Let's break down each question individually:

a) How long will it take to reach home plate?

To find the time it takes for the ball to reach home plate, we can use the horizontal distance and the initial horizontal velocity. In this case, the horizontal distance is 60.5 feet, and the initial horizontal velocity is 139 ft/s.

The formula used is time = distance / velocity, where
- Time is the time taken to reach home plate,
- Distance is the horizontal distance covered (60.5 feet), and
- Velocity is the initial horizontal velocity (139 ft/s).

Therefore, the time taken to reach home plate would be:
Time = 60.5 feet / 139 ft/s.

b) How far did the ball drop on the way to home plate?

Since the ball is thrown horizontally, there is no initial vertical velocity. Thus, we can use the formula for vertical displacement due to gravity and time:

Vertical displacement = (1/2) * acceleration due to gravity * (time)^2,

where
- Vertical displacement is the distance the ball drops (in this case),
- Acceleration due to gravity is 32.2 ft/s^2 (approximately), and
- Time is the time taken as found in part (a).

To find the distance the ball drops, we need to find the vertical displacement.

c) What would be the height of the ball above the ground when it reaches home plate?

In this case, we need to calculate the initial vertical position at which the ball was released from the pitcher's hand (which is 5.3 feet above the ground), and add the vertical displacement calculated in part (b).

To summarize:
a) Time taken to reach home plate = 60.5 feet / 139 ft/s.
b) Distance the ball drops = (1/2) * 32.2 ft/s^2 * (time)^2.
c) Height of the ball above the ground when it reaches home plate = Initial height + Distance the ball drops.

Using these principles, calculations can be made to obtain the specific values.