2Mg + O2 --> 2MgO
REMEMBER our mole ratio is 2Mg:1O2, 2Mg:2MgO, 1O2:2MgO
So if we had 3Mg how much O2?
(3Mg)(1O2/2Mg) = 1.5O2
How much MgO could be produced from 3O2?
you have two Mg for every one O2
so
mols Mg/mols O2 = 2/1
3 mols Mg ( 1 mol O2 / 2 mols Mg) = 3/2 = 1.5 mols O2 ----- Yes
1 O2/2 MgO
3 O2 ( 2 MgO/1 O2 ) = 6 MgO
To determine how much MgO could be produced from 3O2, we need to use the mole ratio from the balanced chemical equation, which is 2MgO:1O2.
First, convert the given quantity of O2 into moles:
3O2 x (1 mole O2/32 grams O2) = 0.09375 moles O2
Now, use the mole ratio from the balanced equation to find the number of moles of MgO that could be produced:
0.09375 moles O2 x (2 moles MgO/1 mole O2) = 0.1875 moles MgO
So, 0.1875 moles of MgO could be produced from 3O2.
To determine how much MgO could be produced from 3 O2, we can use the mole ratio 2 MgO:1 O2 from the balanced equation.
(3 O2) * (2 MgO/1 O2) = 6 MgO
Therefore, 6 MgO could be produced from 3 O2.