2Mg + O2 --> 2MgO

REMEMBER our mole ratio is 2Mg:1O2, 2Mg:2MgO, 1O2:2MgO

So if we had 3Mg how much O2?
(3Mg)(1O2/2Mg) = 1.5O2

How much MgO could be produced from 3O2?

you have two Mg for every one O2

so
mols Mg/mols O2 = 2/1

3 mols Mg ( 1 mol O2 / 2 mols Mg) = 3/2 = 1.5 mols O2 ----- Yes

1 O2/2 MgO

3 O2 ( 2 MgO/1 O2 ) = 6 MgO

To determine how much MgO could be produced from 3O2, we need to use the mole ratio from the balanced chemical equation, which is 2MgO:1O2.

First, convert the given quantity of O2 into moles:

3O2 x (1 mole O2/32 grams O2) = 0.09375 moles O2

Now, use the mole ratio from the balanced equation to find the number of moles of MgO that could be produced:

0.09375 moles O2 x (2 moles MgO/1 mole O2) = 0.1875 moles MgO

So, 0.1875 moles of MgO could be produced from 3O2.

To determine how much MgO could be produced from 3 O2, we can use the mole ratio 2 MgO:1 O2 from the balanced equation.

(3 O2) * (2 MgO/1 O2) = 6 MgO

Therefore, 6 MgO could be produced from 3 O2.