Math

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1) If Keith drove 259 miles of a 500-mile trip and his wife drove the rest of the way, what percent of the trip did his wife drive?
a) 25.9%
b) 48.2%
c) 49.8%
d) 51.8%
e) 74.1%

2) If 150% of J is equal to half of K, and K is not equal to 0, then J/K =
a) 1/5
b) 1/3
c) 1/2
d) 2
e) 3

3) The length of a radius of a circle is decreased by 10%. This causes the area to be decreased by
a) 19%
b) 20%
c) 21%
d) 25%

  • Math -

    1. find what percentage of the trip Keith drove, then his wife must have driven the remaining percentage

    2.
    1.5J = (1/2)K
    3J = K
    divide by K
    3J/K = 1
    divide by 3
    J/K = 1/3

    3. with radius r, area = πr^2
    reduce radius by 10% ---> new radius = .9r
    new area = π(.9r)^2 = .81π
    decrease = .19π
    .19π/π = .19 or 19%

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