Algebra

posted by Emma

The height of a ball thrown directly up with a velocity of 40 feet per second from a initial height of of 5 feet is given by the equation h(t)=-16t^2+40t+5, where t is the time in seconds and h is the ball’s height, measured in feet. When will the ball hit the ground? Round your answer to the nearest tenth.

1. Reiny

When it hits the ground , h(t) = 0 , so

-16t^2 + 40t + 5 = 0
16t^2 - 50t - 5 = 0

Now solve this quadratic using the method that you learned.
One of the answers will be negative, you would reject that one.

2. Anonymous

12

3. john

2.5

Similar Questions

1. ap calculus

The height s of a ball, in feet, thrown with an initial velocity of 112 feet per second from an initial height of 6 feet is given as a function of time t (in seconds) by s(t)=-16t^2+112t+20. 1. What is the maximum height of the ball?
2. Pre-Calc

The height s of a ball, in feet, thrown with an initial velocity of 112 feet per second from an initial height of 20 feet is given as a function of time t (in seconds) by s(t)= -16t^2+112t+20. What is the maximum height of the ball?
3. Algebra

THe function h(t)=-16t^2+v0t+h0 describes the height in feet above the ground h(t) of an object thrown vertically from a height of h0 feet, with an initial velocity of v0 feet per second, if there is no air friction and t is the time …
4. Algebra

THe function h(t)=-16t^2+v0t+h0 describes the height in feet above the ground h(t) of an object thrown vertically from a height of h0 feet, with an initial velocity of v0 feet per second, if there is no air friction and t is the time …
5. calculus

a ball is thrown directly upward with a velocity of 40 feet/seconds. its height in feet after t seconds is given by h(t)equals 40t-16t squared
6. calculus

a ball is thrown directly upward with a velocity of 40 feet/seconds. its height in feet after t seconds is given by h(t)equals 40t-16t squared
7. calculus

a ball is thrown directly upward with a velocity of 40 feet/seconds. its height in feet after t seconds is given by h(t)equals 40t-16t squared
8. Math 1105

- The heights of a ball (in feet) thrown with an initial velocity of 90 feet per second from an initial velocity of 90 feet per second from an initial height of 4 feet is given as a function of time t(in seconds)by s(t)= -16t^2+90t+4
9. algebra

A ball is thrown into the air with an upward velocity of 40 feet per second. Its height, h, in feet after t seconds is given by the function h(t)=-16t^2+40t+10. a. What is the ball’s maximum height?
10. Algebra

A ball is thrown in an upward direction off a platform that is 45 feet high with an initial velocity of 60 feet per second. The height, in feet, of the ball at the time t is given by h(t)= -16t^2 + 60t + 45. The time, t, is given in …

More Similar Questions