posted by nialleen
The area of a rectangle is 2x^2+5x^2-x-6 cm. write a polynomial that represents its width if its length is 2x^2+ x-3.
You must have meant:
area is 2x^3+5x^2-x-6
if so, then it factors nicely into
and the width of 2x^2 + x - 3 factors to (2x+3)(x-1)
(2x^3+5x^2-x-6) ÷ (2x^2+ x-3)
= (x-1)(x+2)(2x+3)/( (2x+3)(x-1) )
you could do a long algebraic division as it stands and also get x+2
thanks a lot!