math

posted by nialleen

The area of a rectangle is 2x^2+5x^2-x-6 cm. write a polynomial that represents its width if its length is 2x^2+ x-3.

  1. Reiny

    You must have meant:
    area is 2x^3+5x^2-x-6

    if so, then it factors nicely into
    (x-1)(x+2)(2x+3)
    and the width of 2x^2 + x - 3 factors to (2x+3)(x-1)

    then
    (2x^3+5x^2-x-6) ÷ (2x^2+ x-3)
    = (x-1)(x+2)(2x+3)/( (2x+3)(x-1) )
    = x+2

    or

    you could do a long algebraic division as it stands and also get x+2

  2. nialleen

    thanks a lot!

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