algebra 2
posted by Taylor .
Find the inverse of each function, if it exists.
f(x)=1/3x5
y=1/3x5
x=1/3y5
x5=1/3y
y=the square root of x5/3

Is this supposed to be the solution to finding the inverse of
y = 1/3x  5 ???
I suggest a 2step process
1. interchange the x and y variables
> x = 1/3y  5
(you had that)
2. now solve this new equation for y
x = 1/3y  5
x+5 = 1/3y
times 3
3x + 15 = y
so f^1 (x) = 3x+15
Why did you involve a square root ??