calculus
posted by Natalie .
Find a point c satisfying the conclusion of the Mean Value Theorem for the function f(x)= x^1/3 on the interval [1,8]
I got f'(c)= 1/7 but am not sure where to go from there.

f'(x)=1/3 (x)^2/3
f (1)=1^1/3=1
f (8) = 2
so, the point c must be such that
f'(c)= (f(8)f(1))/(81)=(21)/7=1/7
but f'(c)=1/3 (c)^2/3 and f'(c)=1/7 so
1/7=1/3(c^2/3)
3/7=c^2/3
take each side to the 3/2 power
c^2/3=7/3
c= cube root (7/3)^2 = 1.76
so, the conclusion of the theorem is borne out.