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250 gms of Zn (65.5) gave 242 gms of ZnO on ignition. Calculate %age yield of the reaction.

  • chemistry -

    2Zn + O2 ==> 2ZnO

    mols Zn = grams/molar mass = ?
    Convert mols Zn to mols ZnO
    Then g ZnO = mols ZnO x molar mass ZnO. This is the theoretical yield (TY). The actual yield (AY) is 242.
    %yield = (AY/TY)*100 = ?

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