Honors Chemistry

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If 72.4 kJ of heat is supplied to a 752 g block of metal, the temperature of the metal increases by 9.95°C. Calculate the specific heat capacity of the metal in J/g·°C.

I cannot find the information in my textbook, and I don't understand the equation needed to do the work on the summer assignment...

  • Honors Chemistry -

    q = mc*delta T
    q = heat = 72,400J
    m = 752g
    c = specific heat = ?
    dT = 9.95

    Solve for c.

  • physical chemistry -

    q = mcdT
    72 400 = 752 X C X 9.95
    C = 9.676 J/C

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