# mat/117

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Select the approximate values of x that are solutions to f(x)=0, where f(x)=-3x^2+3x+9

• mat/117 -

-3x^2+3x+9=0
x^2 - x - 3 = 0

x = (1 ±√13)/2

• mat/117 -

F(x) = -3x^2 + 3x + 9 = 0
Divide by -3:
x^2 - x - 3 = 0
Use Quadratic Formula and get:
X = 2.30, and -1.30 = Approx. 2, and 3.

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