Mr. Jones got a loan for a sum of money, and at the time of repayment he owned $75.00 in interest. Mr. Brown borrowed three times the amount of money Mr. Jones had borrowed at the same rate of interest for twice as long a time. How much interest does Mr. Brown pay?

If Jones borrowed $j at a rate r, he paid 75.00 in interest. So, we see that

jr = 75
(3j)*r*2 = 3*2*jr = 6*75 = 300

Thanks Steve

for the discrete random variable X, where X is the number of credit cards people own in a bank the probability distribution is given by two function. a. find the value of constant k

6*75 is actually 450

To find out how much interest Mr. Brown pays, we first need to determine the amount of money he borrowed.

Let's assume that Mr. Jones borrowed x dollars. Since he had to pay $75.00 in interest, we can set up the following equation:

75 = x * r * t

Where r represents the rate of interest, and t represents the time in years.

Now, according to the problem statement, Mr. Brown borrowed three times the amount of money Mr. Jones borrowed. So, Mr. Brown borrowed 3x dollars.

It is also given that Mr. Brown borrowed at the same rate of interest, and for twice as long a time. Therefore, the time for Mr. Brown's loan is 2t years.

Now, we can calculate the interest paid by Mr. Brown using the formula:

Interest = Principal * Rate * Time

Interest = (3x) * r * (2t)

Simplifying the expression, we get:

Interest = 6xrt

Therefore, Mr. Brown pays 6 times the interest that Mr. Jones paid, which is 6 * $75.00 = $450.00.

Hence, the interest paid by Mr. Brown is $450.00.