The concentration of vinegar was obtained by titration. 20 ml of vinegar required 43.2 ml of 0.350 M sodium hydroxide. Find the concentration of vinegar
mols NaOH = M x L = ?
mols vinegar = mols NaOH
M vinegar = mols vinegar/L vinegar = ?
moles of NaOH= 0.01512moles
concentration of vinegar=0.756moles/L
To find the concentration of vinegar, we can use the following equation:
Moles of sodium hydroxide (NaOH) = Moles of acetic acid (vinegar)
First, let's calculate the moles of sodium hydroxide (NaOH) used in the titration:
Moles of NaOH = Volume of NaOH (in liters) × Concentration of NaOH
Volume of NaOH = 43.2 ml = 43.2 / 1000 = 0.0432 L (converted to liters)
Concentration of NaOH = 0.350 M
Moles of NaOH = 0.0432 L × 0.350 M = 0.01512 moles
Since the molar ratio between NaOH and acetic acid (vinegar) is 1:1, the moles of acetic acid (vinegar) will also be 0.01512 moles.
Given that the volume of vinegar used in the titration is 20 ml or 0.020 L, we can calculate the concentration of vinegar as follows:
Concentration of vinegar = Moles of acetic acid (vinegar) / Volume of vinegar (in liters)
Concentration of vinegar = 0.01512 moles / 0.020 L = 0.756 M
Therefore, the concentration of vinegar is 0.756 M.
To find the concentration of vinegar, we can use the concept of stoichiometry. In this case, we will use the balanced chemical equation between acetic acid (the main component of vinegar) and sodium hydroxide:
CH3COOH (acetic acid) + NaOH (sodium hydroxide) → CH3COONa (sodium acetate) + H2O
Based on the equation, we can see that 1 mole of acetic acid reacts with 1 mole of sodium hydroxide to produce 1 mole of sodium acetate and 1 mole of water.
Given that 20 ml of vinegar (acetic acid solution) required 43.2 ml of 0.350 M sodium hydroxide, we can relate the moles of acetic acid and sodium hydroxide using the equation:
Moles of acetic acid = Moles of sodium hydroxide
To calculate the moles of sodium hydroxide used, we need to multiply the volume (in liters) by the molarity:
Moles of sodium hydroxide = (0.0432 L) × (0.350 mol/L)
Now that we know the moles of sodium hydroxide, we can calculate the moles of acetic acid:
Moles of acetic acid = Moles of sodium hydroxide = 0.0432 L × 0.350 mol/L
The concentration of acetic acid (vinegar) can be calculated by dividing the moles of acetic acid by the volume (in liters) of vinegar used in the titration:
Concentration of acetic acid = Moles of acetic acid / Volume of vinegar (in L)
To convert the 20 ml of vinegar to liters, we divide by 1000:
Volume of vinegar (in L) = 20 ml / 1000 = 0.020 L
Now, we can plug the values into the equation:
Concentration of acetic acid = (0.0432 mol) / (0.020 L)
Simplifying the equation gives us the final result:
Concentration of acetic acid = 2.16 M
Therefore, the concentration of vinegar is 2.16 M.