Determine the percent composition of sodium hydrogen carbonate.
Na H C O3
1*22.999 1*1.008 1*12.011 3*15.999
22.999 1.008 12.011 47.997
/84.015 /84.015 /84.015 /84.015
.2737 .0120 .1430 .5713
*100 *100 *100 *100
27.37% 1.2% 14.3% 57.13%
did i do this correctly?
Yes, you have correctly calculated the percent composition of sodium hydrogen carbonate.
To determine the percent composition, you need to calculate the molar mass of each element in the compound and then divide it by the molar mass of the whole compound. Multiply the result by 100 to get the percentage.
In this case, the molar mass of Na is 22.999 g/mol, H is 1.008 g/mol, C is 12.011 g/mol, and O is 15.999 g/mol. The molar mass of sodium hydrogen carbonate (NaHCO3) is the sum of the molar masses of its individual elements:
NaHCO3 = 22.999 g/mol (Na) + 1.008 g/mol (H) + 12.011 g/mol (C) + 3 * 15.999 g/mol (O) = 84.015 g/mol
Now, divide the molar mass of each element by the molar mass of the compound and multiply by 100 to get the percent composition:
Na: (22.999 g/mol / 84.015 g/mol) * 100 = 27.37%
H: (1.008 g/mol / 84.015 g/mol) * 100 = 1.2%
C: (12.011 g/mol / 84.015 g/mol) * 100 = 14.3%
O: (3 * 15.999 g/mol / 84.015 g/mol) * 100 = 57.13%
Therefore, the percent composition of sodium hydrogen carbonate is 27.37% sodium (Na), 1.2% hydrogen (H), 14.3% carbon (C), and 57.13% oxygen (O).