Write an equation for the reaction that takes place when each base is added to water. A) LiOH B) (CH3)2NH.
LiOH(s) + H2O(l) ==> Li^+(aq) + OH^-(aq)
dimeNH(l) + H2O(l) ==> dimeNH2^+(aq) + OH^-(aq)
A) When LiOH (Lithium hydroxide) is added to water, it dissociates to form lithium ions (Li+) and hydroxide ions (OH-). The equation for this reaction is:
LiOH (s) → Li+ (aq) + OH- (aq)
B) When (CH3)2NH (Dimethylamine) is added to water, it also dissociates to form dimethylammonium ions (CH3)2NH2+ and hydroxide ions (OH-). The equation for this reaction is:
(CH3)2NH (g) + H2O (l) → (CH3)2NH2+ (aq) + OH- (aq)
To write an equation for the reaction that takes place when each base is added to water, we need to first understand the properties of the bases. Bases are substances that can donate hydroxide ions (OH-) to the solution when dissolved in water.
A) LiOH:
When lithium hydroxide (LiOH) is added to water, it dissociates to form lithium cations (Li+) and hydroxide anions (OH-). The equation for this reaction can be written as:
LiOH(s) → Li+(aq) + OH-(aq)
B) (CH3)2NH:
Dimethylamine, represented as (CH3)2NH, is a weak base. It reacts with water to form the corresponding ammonium ion and hydroxide ion. The equation for this reaction can be written as:
(CH3)2NH + H2O → (CH3)2NH2+(aq) + OH-(aq)
So, the equation for the reaction when each base is added to water is:
A) LiOH(s) → Li+(aq) + OH-(aq)
B) (CH3)2NH + H2O → (CH3)2NH2+(aq) + OH-(aq)