A car traveling with an initial velocity of 15.5 m/s accelerates at a constant rate of 3.0
m/s2
for a time of 3.6 seconds.
(a) What is its velocity at the end of this time?
A) 26.3 m/s
B) 18.5 m/s
C) 10.8 m/s
D) 22.1 m/s
E) 19.1 m/s
V=Vo+at
v=15.5+3(3.6)
v=15.5+10.8
v=26.3 m/s
To find the velocity of the car at the end of 3.6 seconds, we can use the equation of motion that relates velocity, acceleration, and time:
final velocity (v) = initial velocity (u) + acceleration (a) * time (t)
Given:
- Initial velocity (u) = 15.5 m/s
- Acceleration (a) = 3.0 m/s^2
- Time (t) = 3.6 seconds
Plugging in these values into the equation:
v = u + a * t
v = 15.5 m/s + 3.0 m/s^2 * 3.6 s
Calculating the right side of the equation:
v = 15.5 m/s + 10.8 m/s
Simplifying:
v = 26.3 m/s
Therefore, the velocity of the car at the end of 3.6 seconds is 26.3 m/s.
So, the correct answer is A) 26.3 m/s.