Hello could you help me answer to one question please.
From 98% Sulphuric acid to make 50ml 5% sulphuric acid How to DIlute
with water , how much need ?
mL1 x %1 = mL2 x %2
mL1 x 98% = 50 mL x 5%
Solve for mL 1.
Add that amount to 50 mL volumetric flask and make to the mark with distilled H2O.
so how much sulphuric acid ml need and how much water?
Of course, I can help you with that! To dilute 98% sulfuric acid to make a 5% sulfuric acid solution, you will need to calculate the volume of water to add.
First, let's determine the amount of sulfuric acid you need to dilute. We can use the equation:
C₁V₁ = C₂V₂
Where:
C₁ = initial concentration (98%)
V₁ = initial volume (unknown)
C₂ = final concentration (5%)
V₂ = final volume (50 ml)
Now, let's plug in the known values into the equation and solve for V₁:
(98%)(V₁) = (5%)(50 ml)
V₁ = (5%)(50 ml) / (98%)
V₁ ≈ 2.55 ml
So, you will need approximately 2.55 ml of 98% sulfuric acid for the dilution.
Next, we need to determine the volume of water to add. Subtract the volume of sulfuric acid from the final volume:
Volume of water = final volume - volume of sulfuric acid
Volume of water = 50 ml - 2.55 ml
Volume of water ≈ 47.45 ml
Therefore, you will need to add approximately 47.45 ml of water to the 2.55 ml of 98% sulfuric acid to make a 50 ml 5% sulfuric acid solution.