a locomotive pulls 10 identical freight cars. the force between the locomotive and the first car is 100,000 Newtons, and the acceleration of the train is 2m/s^2. there is no friction to consider.what is the force between the ninth and tenth cars?

Question

a locomotive pulls 10 identical freight cars. the force between the locomotive and the first car is 100,000 Newtons, and the acceleration of the train is 2m/s^2. there is no friction to consider.what is the force between the ninth and tenth cars?

Answer 1

To determine the force between the ninth and tenth cars, we first need to understand the concept of Newton's second law of motion. It states that the force acting on an object is equal to its mass multiplied by its acceleration.

In this problem, we know that the acceleration of the train is 2 m/s^2. However, to find the force between the ninth and tenth cars, we need to determine the total force applied by the locomotive to pull the entire train.

Since there is no friction to consider, the only force acting on the entire train is the force applied by the locomotive to the first car. Each subsequent car pulls on the one in front of it, transmitting the force.

To find the total force applied to the train, we can use the equation:

Force = Mass × Acceleration.

Here, the mass can be calculated by summing the masses of all the cars pulled by the locomotive.

However, since the cars are identical, we don't need to know their individual masses. We can work with the concept of "equivalent mass." In this case, the equivalent mass of the entire train will be the mass of one car multiplied by the total number of cars.

Let's assume each car has a mass of 'm' kg, and there are a total of 10 identical freight cars.

So, the mass of the entire train will be:

Mass = m × 10.

Next, we can calculate the total force applied to the train using the formula:

Force = Mass × Acceleration.

Now, we can substitute the given values:

Force = (m × 10) × 2.

This gives us the total force applied to the train.

Finally, since the force between the ninth and tenth cars is transmitted through the train, it will be the same as the force applied by the locomotive to the entire train.

Therefore, the force between the ninth and tenth cars is equal to the total force applied to the train, which is given by:

Force = (m × 10) × 2.

To find the numerical answer, we need to know the value of 'm.'

a locomotive pulls 10 identical freight cars. the force between the locomotive and the first car is 100,000 Newtons, and the acceleration of the train is 2m/s^2. there is no friction to consider.what is the force between the ninth and tenth cars?

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To determine the force between the ninth and tenth cars, we first need to understand the concept of Newton's second law of motion. It states that the force acting on an object is equal to its mass multiplied by its acceleration.