Algebra

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This is giving me a lot of trouble.
Factoring Differences of Squares
Factor Completely
98-8w^2
and can you explain how you got the common factor if there is one please

  • Algebra -

    just recall that a^2-b^2 = (a-b)(a+b)

    So, first, make sure that both terms are perfect squares.

    In this case, they are not. However, if you factor out a 2, you have

    2(49-4w^2)
    49 is 7^2 and 4w^2 = (2w)^2. So, we now have

    2(7-2w)(7+2w)

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