math
posted by rachel .
what is the integral from 2 to 1 of 15sqrt(4x^23) dx

look up you standard form for
∫√(u^2a^2) du
Now, if you let u = 2x, you have
u^2 = 4x^2
du = 2 dx, so dx = du/2
Also, let a = √3
So, now your integral is
15/2 ∫√(u^2a^2) du
and just go for it.