posted by Lilo .
37.5 g of Fe2O3 is added to 240 cm^3 of HCl. The reaction occurs according to equation : 6HCl + Fe2O3 -> 2FeCl + 3H2O
At the end of reaction, 5.5 g of Fe2O3 remain unreacted. Find
A) calculate the molarity of HCl used
B) calculate the mass of FeCl3 produced
You have a typo in the equation.
6HCl + Fe2O3 -> 2FeCl3 + 3H2O
g Fe2O3 reacted = 37.5-5.5 = 32.0g
mols Fe2O3 = grams/molar mass = estimated 0.2
a. mols HCl used = 0.2 x (6 mol HCl/1 mol Fe2O3) = estimated 1.2.
M HCl = mols/L = estd 1.2/0.240 = ?
b. mols FeCl3 = mols Fe2O3 x (2 mol FeCl3/1 mol Fe2O3) = 0.2 x 2/1 = estimated 0.4
g FeCl3 = mols x molar mass = ?