37.5 g of Fe2O3 is added to 240 cm^3 of HCl. The reaction occurs according to equation : 6HCl + Fe2O3 -> 2FeCl + 3H2O
At the end of reaction, 5.5 g of Fe2O3 remain unreacted. Find
A) calculate the molarity of HCl used
B) calculate the mass of FeCl3 produced
You have a typo in the equation.
6HCl + Fe2O3 -> 2FeCl3 + 3H2O
g Fe2O3 reacted = 37.5-5.5 = 32.0g
mols Fe2O3 = grams/molar mass = estimated 0.2
a. mols HCl used = 0.2 x (6 mol HCl/1 mol Fe2O3) = estimated 1.2.
M HCl = mols/L = estd 1.2/0.240 = ?
b. mols FeCl3 = mols Fe2O3 x (2 mol FeCl3/1 mol Fe2O3) = 0.2 x 2/1 = estimated 0.4
g FeCl3 = mols x molar mass = ?
A) To calculate the molarity of HCl used, we need to know the amount of HCl that reacted with the Fe2O3 and the volume of the HCl solution.
1. Find the amount of Fe2O3 that reacted:
Since 37.5 g of Fe2O3 was initially added and 5.5 g remain unreacted, the amount of Fe2O3 that reacted is:
Amount of Fe2O3 reacted = Initial amount - Remaining amount
= 37.5 g - 5.5 g
= 32 g
2. Find the moles of Fe2O3:
Using the molar mass of Fe2O3 (159.7 g/mol), we can calculate the moles of Fe2O3 reacted:
Moles of Fe2O3 reacted = Mass / Molar mass
= 32 g / 159.7 g/mol
≈ 0.20 mol
3. Find the moles of HCl:
From the balanced equation, we know that the mole ratio of HCl to Fe2O3 is 6:1. Therefore, the moles of HCl reacted will be 6 times the moles of Fe2O3 reacted:
Moles of HCl reacted = 6 * Moles of Fe2O3 reacted
= 6 * 0.20 mol
= 1.20 mol
4. Find the volume of HCl solution:
We are given the volume of HCl solution, which is 240 cm^3. However, we need to convert it to liters:
Volume of HCl solution = 240 cm^3 = 240 mL = 0.240 L
5. Calculate the molarity of HCl used:
The molarity (M) of a solution is given by the formula:
Molarity = Moles of solute / Volume of solution in liters
Molarity of HCl = Moles of HCl / Volume of HCl solution
= 1.20 mol / 0.240 L
= 5.00 M (rounded to two decimal places)
Therefore, the molarity of HCl used is 5.00 M.
B) To calculate the mass of FeCl3 produced, we need to convert the moles of FeCl3 formed to mass:
1. Find the moles of FeCl3:
From the balanced equation, we know that the mole ratio of FeCl3 to HCl is 2:6 (or 1:3). Therefore, the moles of FeCl3 formed will be one-third of the moles of HCl reacted:
Moles of FeCl3 formed = (1/3) * Moles of HCl reacted
= (1/3) * 1.20 mol
= 0.40 mol
2. Find the molar mass of FeCl3:
The molar mass of FeCl3 can be calculated by summing the atomic masses of iron (Fe) and three chlorine (Cl) atoms:
Molar mass of FeCl3 = [Molar mass of Fe] + 3 * [Molar mass of Cl]
= 55.85 g/mol + 3 * 35.45 g/mol
= 162.20 g/mol
3. Calculate the mass of FeCl3 produced:
Using the formula:
Mass = Moles * Molar mass
Mass of FeCl3 = Moles of FeCl3 * Molar mass of FeCl3
= 0.40 mol * 162.20 g/mol
= 64.88 g (rounded to two decimal places)
Therefore, the mass of FeCl3 produced is 64.88 g.