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a stone is thrown straight up from a 50m high building and hits the ground at a speed of 37.1m/s. What is the initial velocity and what is the maximum height above the ground that the stone reaches?

  • physics -

    For maximum height, equate PE and KE

    h=(1/2)37.1²/9.8=70.2 m

    at 50m, KE is reduced by mgh
    =19.9 m/s

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