A number whose digit in the ten billions place is 5 less than 8
8 - 5 = 3
3?,???,???,???
To find the number whose digit in the ten billions place is 5 less than 8, we can follow these steps:
Step 1: Start with the value of 8.
Step 2: Subtract 5 from 8.
8 - 5 = 3
Therefore, the number whose digit in the ten billions place is 5 less than 8 is 3.
To find the number described, we first need to understand the place value system. In the place value system, each digit in a number represents a different power of 10.
Let's start by understanding the "ten billions" place value. In the number 8, the "ten billions" place value is the position immediately to the left of the billions place. In other words, it represents the value of the digit multiplied by 10 billion (10,000,000,000).
The problem states that the digit in the ten billions place is 5 less than 8. This means that the digit in the ten billions place is 8 - 5 = 3.
Now that we know the digit in the ten billions place is 3, we can determine the number by placing the digit in the correct position. All other digits will be 0, as they are not mentioned in the problem. Therefore, the number described is 30,000,000,000 (30 billion).