find the distance between (0,9)(-40,0) answer in simplest form id ont know where to start
first place is to check your text for some kind of distance formula.
Next, get out some graph paper and plot the two points, then draw a line between them. Call them A and B, respectively.
Now draw a horizontal line from A and a vertical line from B. Where the two lines intersect, call that point C.
Now you have a right triangle, with the right angle at C, and the hypotenuse is AB.
Now recall your Pythagorean Theorem, which says that if the two legs of a right triangle are a and b, and the hypotenuse is c, then
c^2 = a^2+b^2
That is also your distance formula, where
a = x2-x1 = (-40-0)
b = y2-y1 = (0-9)
So, c^2 = 40^2+9^2 = 1609
c = √1609 = 40.11
If you look carefully at the distance formula
d = √(x2-x1)^2 + (y2-y1)^2)
you see that it's really just the Pythagorean Theorem in the context of coordinates, rather than side lengths.