A solution contains 72.0 g of HCl and 468 g of (C6H6). What is the mole fraction of benzene?
mols HCl = grams/molar mass
mols C6H6 = grams/molar mass
total mols = mols HCl + mols C6H6
Xbenzene = mols benzene/total mols.
To calculate the mole fraction of benzene (C6H6), we first need to determine the moles of both substances present in the solution.
To find the moles of a substance, we use the formula:
moles = mass / molar mass
First, let's calculate the moles of HCl:
mass of HCl = 72.0 g
molar mass of HCl = 36.46 g/mol
moles of HCl = 72.0 g / 36.46 g/mol = 1.97 mol (rounded to two decimal places)
Next, let's calculate the moles of benzene (C6H6):
mass of benzene = 468 g
molar mass of benzene = 78.11 g/mol
moles of C6H6 = 468 g / 78.11 g/mol = 5.99 mol (rounded to two decimal places)
Now, we can find the mole fraction of benzene (C6H6) using the formula:
mole fraction = moles of benzene / total moles of the solution
mole fraction of C6H6 = 5.99 mol / (1.97 mol + 5.99 mol) = 0.75 (rounded to two decimal places)
Therefore, the mole fraction of benzene (C6H6) in the solution is 0.75.