I am a decimal between 2 and 3. The digit in my thousandths place is the sum of the digits in my tenths and hundredths place. The digit in my tenths place is the difference of the digits in my thousandths and hundredths place. The digit in my hundreths place is one less than the digit in my thousansths place. What decimal number I am?
.189
.178
.156
.145
.134
.123
Which do you want to use?
what's the trouble? Just start working in the clues. The number is
2.abcdefg...
c = a+b
b = c-a (well, duh)
b = c-1
It appears that the number is just
2.abc
c = a+c-1
a = 2c+1
Now, since a < 10, c < 5
So, if a = 0,1,2,3,4
then c = 1,3,5,7,9
and b = 1,2,3,4,5
So, we could have
2.011
2.123
2.235
2.347
2.459
If you don't want to allow repeated digits, then the only choices are
2.347
2.459
Most of Steve's answers do not fit the requirement of "The digit in my hundreths place is one less than the digit in my thousansths place."
Dang. Don't know what I was thinking.
2.134
To find the decimal number that satisfies these conditions, we can break down the given information step by step:
Step 1: The digit in the thousandths place is the sum of the digits in the tenths and hundredths place.
Let's call the digit in the thousandths place as A, the digit in the tenths place as B, and the digit in the hundredths place as C.
Therefore, A = B + C.
Step 2: The digit in the tenths place is the difference of the digits in the thousandths and hundredths place.
Using the same variables, B = A - C.
Step 3: The digit in the hundredths place is one less than the digit in the thousandths place.
Using the same variables, C = A - 1.
Now, we can substitute the values of B and C from Step 2 and Step 3 into Step 1 to simplify the equation:
A = (A - C) + C
A = A
This equation tells us that A can be any digit between 0 and 9. Therefore, the decimal number that satisfies all the given conditions can be any number between 2.000 and 3.999, as long as the digits in the thousandths, tenths, and hundredths place follow the given relationships.
For example, if A = 5, B = (A - C) = 4, and C = (A - 1) = 4, then the decimal number would be 2.544.
Similarly, if A = 3, B = (A - C) = 1, and C = (A - 1) = 2, then the decimal number would be 2.132.
In summary, the decimal number that satisfies the given conditions can be any number between 2.000 and 3.999, as long as the relationships described in the question are followed.