Math
posted by Nihira .
Prove the identity
csc^2x = 2sec2x / sec2x  1
Sorry i really tried. I got : LS = 1  (cos^2x/sin^2x) but that's it. please help

multiply RS top and bottom by cos2x and you have
2/(1cos2x)
= 2/(1(cos^2 x  sin^2 x))
= 2/(1cos^2 x + sin^2x)
= 2/(2sin^2 x)
= 1/sin^2 x
= csc^2 x
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